Question

a man buys a plot of land for rupees 72000 he sells one third of the land at a loss of 20% and two-fifth of at the gain of 25% at what price must he sell the remaining so as to make a overall profit of 10% percent

Answer 1

Step-by-step explanation:

Let's assume that the price of each part sold is proportional to the size of the plot (i.e 1/3 of plot= 1/3 of 72000 = 24000)

however, he sells 1/3rd at a loss of 20%

therefore selling price = (80/100)*24000

=80*240 =19,200

similarly, 2/5th of the plot is sold at a gain of 25%

therefore S.P = (125/100)*(2/5)*72000

=28,800

now, for the man to get a profit of 10% on the whole, his total S.P should be (110/100)*72000

=79200

so far, on the plots he has already sold, the money obtained is 19,200+28,800

=48,000

therefore, the last part should be sold at a price of (79200-48000) = 31,200