A man buys a rectangular plot. To beautify it, he makes two semi-circular portions where
he grows flower and in the remaining part he grows wheat. The figure is as follows.
1 What is the area of the rectangular field PQRS?
2 Find the area of the semicircular portion where he grows flowers with QR as diameter.
3 Find the cost of manuring one semi-circular portion at ₹4 per sq cm.
4 Find the area of the portion where he can grow wheat.
Answers
Answer:
Ex 9.3, 1 - Chapter 9 Class 9 - Areas of Parallelograms and Triangles (Deleted)
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Ex 9.3, 1 - Chapter 9 Class 9 Areas of Parallelograms and Triangles - Part 2
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1. Area Of Rectangular field= L×B = 10cm × 7 cm
=70cm square.
2. Area of semicircular portion= πr2
= 22/7 × 3.5 × 3.5= 38.5cm square
3. Cost of Manuring 1 cm square = ₹4
Cost of manuring 38.5cm2 = ₹4 × 38.5 = ₹154
4. Area of the portion where he can grow wheat =
Area of the field - area of semicircular portion
Therefore, the portion where he can grow wheat = 70- 38.5 = 31.5 cm square.