Math, asked by punithchowdary5447, 1 year ago

A man buys a scooter for rupees 22000.He pays rs4000cash and agrees to pay the balance in annual installment of rs 1000 plus 10% interest

Answers

Answered by 32725000

Given initial payment =Rs.4,000

The balance amount =22,000−4000=Rs.18000

Also given that the payment in each installment =1000+ 10% interest on the unpaid amount.

⇒ payment in 1st year =1000+10100.18000

Payment in 2nd year =1000+10100.(18000−1000)=1000+10100.(17000)

Payment in 3rd year =1000+10100.(18000−2000)=1000+10100.(16000)

an so on

Total amount paid in all the installments is

S=[1000+10100.18000]+[1000+10100.17000]+[1000+10100.16000]+..........

=[1000+1000+.......ntimes.]+10100[18000+17000+16000+.......tn]

32725000: We have to find the no.of terms n .
The last term in this series tn is 1000
We know that tn=a+(n−1)d
⇒1000=18000+(n−1)(−1000)
⇒−17000=(n−1)(−1000)
⇒n=18
We know that sum of n terms of an A.P. =n2(a+tn)
∴18000+17000+16000+.........1000=182[18000+1000]
=9(19000)=171000
∴ 10100.171000=17100

32725000: 1000+1000+.......ntimes =1000×18=18000
∴ the total amount paid through installments =18000+17100=35100
∴ The tractor cost for the farmer =4000+35100=Rs.39100

32725000: here is the whole answer for you

32725000: please mark this the brainiest

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