Math, asked by 123531, 1 year ago

A man buys avbox of fruits containing 286 fruits.Out of these1/2 of the fruits are apples and the rest pears .4/13 of the pears are rotten.If he sells the good pears at ₹ 4 1 by 11 each,then the money he receives on selling them is

Answers

Answered by gjjadhav1
5
286÷2=143

therefore 143 are apples
143 are pears

A/Q
out of 143 4/13 are rotten
143÷9/13=99 (4/13 are rotten therfore remaining
are 9/13)
A/Q

9 groups are created because 99÷11=9
therefore
9×41=269

ans is rupees 169
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