Question

A man buys bananas at 5 for a rupee and sell them at 9 for rs 2 and gains rs 3. Find the no of bananas he sold.

Answer 1

I assume you mean 1 pen each @Rs.9 and Rs.10

He hence pays Rs. 19 for 2 pens.

he sells @ Rs. 15

hence he makes a net loss of Rs.4.00

In % this is approx 21% loss.

just change pencil for banana

Answer 2

The number of bananas sold = 135

Explanation:

Given : A man buys bananas at 5 for a rupee.

i.e.  Cost of 5 bananas = Re 1

Then,   Cost of one banana = Re  $\dfrac{1}{5}$

Selling price of 9 bananas = Rs 2

Selling price of one banana = Rs $\dfrac{2}{9}$

Gain on one banana =  Selling price - Cost price of one banan

= $\dfrac{2}{9}-\dfrac{1}{5}=\dfrac{10-9}{45}=\dfrac{1}{45}$

Number of bananas need to sold to gain Rs 3 =  (Rs 3) ÷ (Gain on one banana )

= $3\div\dfrac{1}{45}$

$=3\times45=135$

So , the number of bananas sold = 135

# Learn more :

A man buy bananas at 5 for rupees 6 and sell them at 2 for rupees 3. Find his loss or gain per cent

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