Question

⭐A man buys certain number of TV sets at total cost of Rs 42,000 the cost of each TV set being the same. had he bought one TV set more, the price of each set would have been less by Rs.100.how many TV sets did he purchase?⭐

CLASS 10 CHAPTER:QUADRATIC EQUATIONS

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Answer 1

hey mate
refer to attachment

Answer 2

$\huge{\mathfrak{heya!!}}$
.

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Let the total no of TV sets he bought be x

Total cost of x TV sets =Rs 42,000

So, cost of each TV set =
$\frac{42000}{x}$

According to question:-

$\frac{42000}{x + 1} = \frac{42000}{x} - 100$
$\frac{42000}{x } - \frac{42000}{x + 1} = 100 \\ \\ \\42000( \frac{1}{x} - \frac{1}{x + 1} ) = 100 \\ \\ \frac{1}{x} - \frac{1}{x + 1} = \frac{1}{420} \\ \frac{1}{ {x}^{2} + x} = \frac{1}{420} \\ \\ {x}^{2} + x - 420 = 0 \\ \\ {x}^{2} + 21x - 20x - 420 = 0 \\ \\ (x - 20)(x + 21) = 0$
so the value of x=. 20, not 21 because no of tv sets can't be negative.

So he bought 20 TV sets

Thanks