Question

A man buys some lemons at 4 for a rupee and the same number of lemons at 5 for a rupee. He mixes them and sells them at 9 for Rs 2. find the gain or loss percent.

Answer 1

Answer:

Let cost of 4 lemons=Rs 1

Cost of 1 lemon  $=\frac{1}{4}$

Cost of 5 lemon = Rs 1

Cost of 1 lemon  $=\frac{1}{5}$

Cost of two lemon if one cost  4 for a rupee and another cost 5 for a rupee  

$=\frac{1}{4}+\frac{1}{5}\\\\=\frac{9}{20}$

Selling price of 9 lemons=Rs 2

Total cost of, 9 lemons =Rs 2

Cost of 1 lemon at  $=\frac{2}{9}$

Cost of 2 lemon  $=\frac{4}{9}$

As, $\frac{9}{20}>\frac{4}{9}$

So, loss= Cost price of two lemons -Selling price of two lemons

$=\frac{9}{20}-\frac{4}{9}\\\\=\frac{1}{180}\\\\{\text{loss percent}}=\frac{\text{loss}}{\text{Cost price}}\times 100\\\\=\frac{\frac{1}{180}}{\frac{9}{20}}\times 100=\frac{100}{81}=1.23$

Loss percent =1.23 %