Question

A man buys two articles at Rs 410. He sells both at the same prise .On one he makes a profit of 15% and on the other a loss of 10% .Assuming the cost prise of the article on Which he makes profit to be x,obtain an equation .Also, find the cost price of both the articles.

Answer 1

let 1st article be x & 2nd be y .
x+y=410
x=410-y
x+15/100x + y-10/100y=410
115x/100 + 90y/100=410
115x + 90y= 41000
23x + 18y = 8200 -(1)
put x =410-y in 1
23(410-y) +18y=8200
9430 - 23y+18y=8200
-5y= -1230y
y=246
x=410 -246
x=164

Answer 2

Step-by-step explanation:

this is accurate answer