A man buys two bat one for rupees 1360 and another for rupees 1040. he sells the first bat at gain of 15% and the second bat at loss of 15%. find hos gain or loss percent in whole transaction.
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Answered by
15
cost price of the first bat = 1360
gain percentage = 15%
so selling price
= cost price + gain percentage = 1360 + 15% = 1360 + 204= 1564
cost price of the second bat = 1040
loss percentage = 15%
so selling price
= cost price - loss percentage = 1040 - 15% = 1040 - 156 =884
total cost price amount = 1360 + 1040 = 2400
total sales amount = 1564 + 884 = 2448
here sales > cost..
sp profit exsts..
proft = sales - cost= 2448 -2400 = 48
profit or gain percentage = gain / cost price = (48 / 2400)*100 = 2..
so the gain percentage = 2%
rustyattacker03629:
Sorry, but your 1st method of finding S. P. Is wrong
Answered by
13
C. P. Of 1st bat = ₹1360
Gain = 15%
S. P. = C. P. (100+ gain % / 100)
= 1360 (115 / 100)
= ₹1564
Now, C. P. Of 2nd bat = ₹1040
Loss = 15 %
S. P. = C. P. (100 - loss% / 100)
= 1040(85 / 100)
= ₹884
Therefore, total C.P. of both bats = ₹1360+1040
= ₹2400
Now, total S.P. of both bats = ₹1564 +884
= ₹2448
Here, S. P. >. C. P.
So, profit = S. P. - C. P.
= ₹2448 - 2400
= ₹48
Now, profit% = profit/C.P. x 100
= 48/ 2400 x 100
= 2%
Therefore, profit = 2%
Gain = 15%
S. P. = C. P. (100+ gain % / 100)
= 1360 (115 / 100)
= ₹1564
Now, C. P. Of 2nd bat = ₹1040
Loss = 15 %
S. P. = C. P. (100 - loss% / 100)
= 1040(85 / 100)
= ₹884
Therefore, total C.P. of both bats = ₹1360+1040
= ₹2400
Now, total S.P. of both bats = ₹1564 +884
= ₹2448
Here, S. P. >. C. P.
So, profit = S. P. - C. P.
= ₹2448 - 2400
= ₹48
Now, profit% = profit/C.P. x 100
= 48/ 2400 x 100
= 2%
Therefore, profit = 2%
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