A man buys two cows for rs. 1350. he sells one so as to lose 6% and the other so as to gain 7.5%. on the whole he neither gains nor loses. what is the cost of second cow?
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Heya!
Let the price of the first cow be x and the second's be y.
Then, x + y = 1350
Also, given that in the whole transaction, the man neither gains nor losses which means, numerical value of the loss is equal to the numerical value of profit.
That is, 6% of x = 7.5% of y
or, x : y = 5 : 4
9 (5 + 4) = Rs. 1350 [Since total profit is Rs. 1350]
2nd cow's price = 4/9 × 1350 = 600 (answer)
5/9 × 1350 = Rs. 750 (1st cow) [5 represents the CP of the cow sold at 6% loss]
Hope it helps!!
Let the price of the first cow be x and the second's be y.
Then, x + y = 1350
Also, given that in the whole transaction, the man neither gains nor losses which means, numerical value of the loss is equal to the numerical value of profit.
That is, 6% of x = 7.5% of y
or, x : y = 5 : 4
9 (5 + 4) = Rs. 1350 [Since total profit is Rs. 1350]
2nd cow's price = 4/9 × 1350 = 600 (answer)
5/9 × 1350 = Rs. 750 (1st cow) [5 represents the CP of the cow sold at 6% loss]
Hope it helps!!
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