a man buys two cycle at at Rs 900 .he sold one at the loss of 20%.other one at profit of 25%. on whole transaction he gain Rs 90. find the cost prize of each cycle.
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let cost of one cycle be x and other cycle be y
so x + y = 900 ⇒ y = 900 - x
given (y × 125)/2 - ( x × 80)/100 = 90
((900 - x) × 125)/2 - ( x × 80)/100 = 90
solving x we get x = 505
so cost of cycles = rs 505 and 900 - 505 = rs 395
so x + y = 900 ⇒ y = 900 - x
given (y × 125)/2 - ( x × 80)/100 = 90
((900 - x) × 125)/2 - ( x × 80)/100 = 90
solving x we get x = 505
so cost of cycles = rs 505 and 900 - 505 = rs 395
Anonymous:
hope it hlps
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