Question

A man can kill a birds once in three shots. On this assumption he fires three
shots. What is the probability that the bird is killed ?​

Answer 1

Answer:

the man kill a bird once in three shots .the probability the bird is killed

isp(E)=1/3

there for the probability that a bird is not a killed is

p(E)=1-p(E)=1-1/3=2/3

Answer 2

The probability  that the bird is killed is 0.703

Step-by-step explanation:

let A be the event three shots hit

then

P (A) = $\frac{1}{3}$

then

P (not A) = 1- P (A)

P (not A)

= $1-\frac{1}{3} \\\\\frac{2}{3}$

p (bird killed ) = 1- p(none of  three shots hit )

$1-\frac{2}{3}\times \frac{2}{3}\times \frac{2}{3}\\\\1-0.296\\\\0.703..$

hence , The probability  that the bird is killed is 0.703

#Learn more:

A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed :

https://brainly.in/question/10264398