Question

A man can open a nut by applying a effort of 75 kgf by using a lever of handle of 0.5m. What length of the lever of another handle if the effort required to open the nut is 45 kgf.​

Answer 1

$\huge \underline{ \underline{ { \cal \: {★Q}} \large \red{ \tt \: U} \green{ \tt \: E} \blue{ \tt \: S} \orange{ \tt \: T} \purple{ \tt \: I} \red{ \tt \: O} \blue{ \tt \: N}}} : -$

• A man can open a nut by applying a force of 75 KGF by using a lever of handle of 0.5 metre.What should be the length of the lever of another handle if the force required to open the nut is 45 KGF.

$\underline{ \huge{ \sf \: \ ☯\:\: T} \large\tt{{{ \underline{ \blue{HINGS}}}}}}$$\underline{ \huge{ \sf \: \ G}\large\tt{{{ \underline{ \blue{IVEN} : - }}}}}$

• $\boldsymbol { \underline{★Force \: \: required \: \: to \: \: open \: \: a \: \: nut \: \: \orange➙ \: \red{\tt {\: 75 \: kgf}}}}$

• $\boldsymbol { \underline{★Length \: \: of \: \: the \: \: levers \: \: handle \: \: \orange➙ \: \red{\tt {\: 0.5 \: \bf{m }}}}}$

• $\boldsymbol { \underline{★Force \: \: required \: \: to \: \: open \: \: the \: \: nut \: \: of \: \: another \: \: handle \: \orange➙ \: \red{\tt {\: 45 \: kgf}}}}$

$\underline{ \huge{ \sf \: \ ☯\:\: T} \large\tt{{{ \underline{ \pink{O}}}}}}$$\underline{ \huge{ \sf \: \ F}\large\tt{{{ \underline{ \pink{IND} : - }}}}}$

• $\boldsymbol { \underline{★Length \: \: of \: \: the \: \: lever \: \: of \: \:another\: \: handle \: \: \orange➙ \: \red{\tt {\:??}}}}$

$\underline{ \huge{ \sf \: \ ☯ \:\:F} \large\tt{{{ \underline{ \purple{ORMULA}}}}}}$$\underline{ \huge{ \sf \: \ U}\large\tt{{{ \underline{ \purple{SED} : - }}}}}$

$\boxed{⚫{\bf{\red{\underline{\: \:Note\: :- \: (i) \: means \: case \: 1, \: (ii) \:means \:case\: 2\:. }}}}}$

• $\sf{★Effort\: arm\: (ii) =\dfrac {Effort\: applied\: (i) \times \:Handle's\: length\: (i)}{ Effort\: applied\: (ii)}}$

$\huge \underline{ \underline{ { \cal \: {★S}} \large \red{ \tt \: O} \green{ \tt \: L} \blue{ \tt \: U} \orange{ \tt \: T} \purple{ \tt \: I} \red{ \tt \: O} \blue{ \tt \: N}}} : -$

$\large\frak{\underline{\dag\:The \:work\: done \:to \:open \:the\:nut \:in \:both \:the\: cases\: is\:same.}}$

$\large\sf{\underline{\therefore\: \:work\: done \:in \:case \:(i):\implies \:work\: done \:in \:case \:(ii)}}$

$\huge { \underline{ { \sf \: {•\:\;T}} \large \blue{ \bf{ HEN}, }}}$

$\large\sf{\underline{★Effort\: \times \:effort\: arm\: in\:(i)\: \implies \:effort \: \times \:effort\: arm\: in \:case\: (ii)}}$

$\sf{\underline{★75\:kgf \times \:0.5\: m\: in\:(i)\: \implies \:45 \:kgf \times \:Effort\: arm\: in \:case\: (ii)}}$

$\sf{\therefore\:\:Effort\: arm\: (ii) =\dfrac {75 \: \times\: 0.5\: }{ 45}}$

$\frak{\underline{\dag\:Multiply \:75\: and\: 0.5 \:to \:get \:37.5.}}$

$\sf:{\implies{\dfrac{37.5}{45}}}$

$\frak{\underline{\dag\:Expand\: \dfrac{37.5}{45}\: by\: multiplying\: both\: numerator\: and\: the \:denominator \:by \:10.}}$

$\sf:{\implies{\dfrac{\cancel{375}\:^{5}}{\cancel{450}\:^{6}}}}$

$\frak{\underline{\dag\:Reduce\: the\: fraction \:\dfrac{375}{450} \:to \:lowest\: terms\: by\: extracting\: and\: canceling\: out\: 75.}}$

$\sf:{\implies{\dfrac{\cancel{5}\:\:^{0.83333..}}{\cancel{6}\:^{1}} }}$

$\huge { \underline{ { \sf \: {☯F}} \large \red{ \bf{ ACTOR:-} }}}$

$\sf:{\implies{\dfrac{5}{2 \cdot 3} \approx 0.833333333m}}$

$\huge \underline{ \underline{ { \cal \: {★A}} \large \red{ \tt \: N} \green{ \tt \: S} \blue{ \tt \: W} \orange{ \tt \: E} \purple{ \tt \: R} }} : -$

$\boxed{\sf{★\:\:\: \bigg\lgroup { \red{\dfrac{5}{2 \cdot 3} \approx 0.833333333\:\:m } \bigg\rgroup★}}}$

$\mid\huge \underline{ \overline{ { \cal \: {♪}} \large \red{ \tt \: ♪} \green{ \tt \: •} \blue{ \tt \: •} \orange{ \tt \: •} \purple{ \tt \: •} \red{ \tt \: ✓} \blue{ \tt \: ✓} \mid}}$

Answer 2

Answer:

hello

Happy promise day ❤️❤️