Question

A man can reach a certain place in 30hrs.If he reduces his speed by 1/10 th, he goes 9km less in that time. Find his speed

Answer 1

Answer:

3km/hr

Explanation:

let v be speed of man and s be the distance covered

then initially v=s/30

after he reduces his speed by 1/10 his speed is

v-v/10= 9v/10

now he covers (s-9 )km

so 9v/10= (s-9) /30

as v= s/30

=> s= 30v

then 9v/10= ( 30v-9) /30

9v/10= v- 9/30

9/30= v/10

=> v= 3km/hr