A man can reach a certain place in 30hrs.If he reduces his speed by 1/10 th, he goes 9km less in that time. Find his speed
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Answer:
3km/hr
Explanation:
let v be speed of man and s be the distance covered
then initially v=s/30
after he reduces his speed by 1/10 his speed is
v-v/10= 9v/10
now he covers (s-9 )km
so 9v/10= (s-9) /30
as v= s/30
=> s= 30v
then 9v/10= ( 30v-9) /30
9v/10= v- 9/30
9/30= v/10
=> v= 3km/hr
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