A man can see the object 0.8m away from his eye. what is the power of lens required to correct his vision. (please send the correct answer)
Answers
AnsweR
Step-by-step explanation:
Given:-
Correcting distant vision;
Power P = -5.5D
Using P = (1/f) where f= focal length of the lens.
=> f = (1/-5.5) = -0.181m
The focal length of the lens for correcting distant vision =-0.181m.
Correcting near vision
Power P = + 1.5D
Using P = (1/f) where f= focal length of the lens.
=> f = (1/1.5) = +0.667m
The focal length of the lens for correcting distant vision =+0.667m.
Question 6.
The far point of a myopic person is 80 cm in front of the eye. What is the nature and power of the lens required to correct the problem?
Answer:
For a myopic eye, concave lens should be used to correct the defect;
Object distance u = -infinity
Far point of the defective eye v = -80cm
Using (1/f) = (1/v) – (1/u)
(1/f) = 1/ (-80) + (1/-infinity)
(1/f) = - (1/80) + (-0)
f = -80 cm
f = -0.8 m
Power = (1/f)
= 1/ (-0.8)
= -1.25 D
The nature of lens required to see the distant objects clearly is convex lens is power -1.25 D.
Answer:
Step-by-step explanation:
see the image
