Question

A man can swim at a speed of 10Km/h in still water. He wants to cross a 500m river flowing at 5Km/h . He keeps himself always at an angle of 120° with the rive flow while swimming . (1) Find the time he takes to cross the river 2 ) At what point on opposite bank will he arrive....​

Answer 1

Answer:

The time taken to cross the river is

3

3

1

h

C

The drift of the man along the direction of flow, when he arrives at the opposite bank is

6

3

1

km

We know v=

t

d

t=

v

d

=

vcos30

o

2

1

=

3

2

1

2

1

=

3

3

1

hrs

as you know indirection the are two velocities one is given & another is velocities components

So V

mean=V

given =V

sin30°

=2−3sin30° =23-2 =

21

drift =vt=

21 × 33 =693

1 km

Explanation:

PLEASE MARK ME AS THE BRAINLIEST

Answer 2

I hope this will help you