A man can swim in still water at a speed of 6 kmph
and he has to cross the river and reach just opposite
point on the other bank. If the river is flowing at a
speed of 3 kmph, and the width of the river is 2 km.
the time taken to cross the river is (in hours)
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Answer:
If he swims 6 kmh^-1 .to a inclined to vertical In river plane.
then River is going through 3 kmh^-1
Which makes a obtuse triangle now
if the Result of them is go through the Perpendicular Line to the Horizontal.
then he can swim in the lowest time.
then
6 sin a=3
6 cos a= Result
sin a=0.5
then cos a=(root(3)/2)
so Result is 3 root(3)
now use S=ut
then 2=3root(3)×t
Because of that
t=2/3 root(3) seconds
Explanation:
use Vectors as Velocities
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