A man can swim in still water at a speed of 6km/h and he has to cross the river and reach just
opposite point on the other bank. If the river is flowing at a speed of 3km/h, he has to swim in the
direction
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Given :-
A man has to swim to the opposite side of the other bank.
Drift = 0.
Speed of river in horizontal direction = Vx = 3 Kmh-¹.
|Vx| = 3 Km/h
|Vy| = 6 Km/h
tanØ = |Vx|/|Vy|
tanØ = 3/6
tanØ = 1/2
Ø = tan-¹(1/2)
Hence,
The man has to swin in the direction=Ø=tan-¹(1/2).
Some other information.
To cross the river in shortest distance i.e. to cross the river in straight, the man should swim upstream or downstream making an angle Ø with vertical distance.
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