Question

A man can throw a ball to a maximum height of 'H'. What is the maximum distance he can throw a ball with the same velocity?
Pls help
Will mark brainliest

Answer 1

We know that R = u2 * Sin 2θ / g.

As, the range is maximum, so, θ = 450

So, 80 = u2 /g.

Now, H = height reached by ball = u2 Sin2θ / 2g.

Putting value of θ = 450 , u2 / g = 80, we get

H = 80/4 = 20m

Answer 2

I have solved it out.......Im SAYAN BANERJEE of GHS...FOR MORE HELP PLEASE ASK