Question

A man can throw a stone to a maximum height h. The horizontal diatnce upto

Answer 1

Answer:

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Answer 2

Answer:

Hey Friend here is your answer....

Let the person throw a stone vertically with initial velocity u.

The maximum height attained by the stone is h.

At this height the velocity of the stone is zero, i.e v=0

⇒ v

2

−u

2

=2(−g)h

0−u

2

=−2gh

⇒ h=

2g

u

2 ............(1)

Maximum horizontal range, R

max

=

g

u

2

⇒ R

max

=2h .............(using 1))

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