Question

A man carries a bucket of water of 1kg for 10 m then work done is

Answer 1

hyy....


bcz the force on bucket is vertically upward and it's displacement is horizontal ... ,. angle between them is 90° .

and , a/q to formula

=>> w = f.s.cos theta

=> w = f.s.cos 90° = 0 joule answer


hope this helps !

Answer 2

Answer:

Work done is 0.

Explanation:

• The Force calculation: The man is carrying a bucket of water of mass, m = 1 kg

            The acceleration = acceleration due to gravity

                                         = g = 9.8 m/s², downward direction.

             Applied force = F = mg = 1 × 9.8 N, downward direction.

                                                      = 9.8 N, downward direction.

• Work down:  Displacement, S = 10 m, horizontally.

        Here force and displacement are perpendicular to each other, so angle between them = Ф = 90° and cos90° = 0

        Work down = F . S = F S cosФ = F S cos90° = F S(0) = 0

       So, work done = 0.

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