a man carries a load of 25 kg on his head and walks through distance of 10 km find the work done by them on the road
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The gravitational force on the load is downward and displacement is in horizontal direction.
The work done by a force F newtons in covering a distance of s metres is......
W = Fscos theta.
where theta is the angle between force and displacement.
so .. in this case the angle is 90 degree because force is downward and displacement is in horizontal direction.
Force =mg=25×10=250
displacement=10km=10000m
So W=250×10000×cos90°
cos 90°=0
so work done =250×10000×0=0J
The work done by a force F newtons in covering a distance of s metres is......
W = Fscos theta.
where theta is the angle between force and displacement.
so .. in this case the angle is 90 degree because force is downward and displacement is in horizontal direction.
Force =mg=25×10=250
displacement=10km=10000m
So W=250×10000×cos90°
cos 90°=0
so work done =250×10000×0=0J
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