Question

a man carrying a bag of total mass 25kg climbs upto a height of 10m in 50sec calculate the power delivered by him on the bag​

Answer 1

Answer:

Given:

Mass carried = 25 kg

Height = 10 m

Time taken = 50 sec.

To find:

Power delivered upon the bag by the man.

Concept:

The man does in carrying the bag upto the given height against gravity. Power delivered by him oa given the ratio of work done to the time taken to lift to that height.

Calculation:

$work = m \times g \times h$

$= > work = 25 \times 10 \times 10$

$= > work = 2500 \: joule$

Now calculation of power :

$power = \dfrac{work}{time}$

$= > power = \dfrac{2500}{50}$

$= > power = 50 \: Watt$

So final answer is :

$\boxed{ \red{ \huge{ \bold{power = 50 \: Watt}}}}$

Answer 2

Question :-

A man carrying a bag of total mass 25kg climbs upto a height of 10m in 50sec calculate the power delivered by him on the bag .

Answer :-

$\implies \boxed{ \sf{ \red{power}( p) = 50 \: \: \green{\frac{j}{s}} \: or \: watt \: }} \: \:$

To Find :-

→ Power delivered by man .

Explanation :-

$\green{ \boxed{\bf{ \red{Given}}\begin{cases}\sf{ \orange{mass \: of \: beg \: (m)} = 25kg \: }\\\sf{ \pink{height \: (h) = 10 \:} m}\\ \sf{time \: taken \: (t) = 50 \: s \: }\end{cases} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}$

We know that ;

$\implies \boxed{ \sf{work \: \red{ done \:(w) = } \green{\: m \: g \: h }\: }} \\ \\ \to \: \sf{w = \red{ 25 \times 10 }\times 10} \\ \\ \to \boxed{ \sf{ \blue{ w = 2500} \: j \: }}$

also we know that ;

$\implies \boxed{ \tt{ \green{ power} (p)\: = } \sf \: \frac{ \red{work \: done} \: }{time \: } } \\ \\ \implies \sf{\: p \: = \frac{2500}{50} }\\ \\ \implies \boxed{ \sf{ \red{power}( p) = 50 \: \: \green{\frac{j}{s}} \: or \: watt}} \:$