A man carrying a suitcase of mass 30 kg walks on a horizontal road through a distance of 10 m and then rises 10 m in the vertical direction through a staircase. calculate the total work done.
Answers
Answered by
0
Answer:
3000 J
Explanation:
Opposing force is gravity in horizontal case theoretically no work is done since change in total energy is zero in vertical direction it is
mgh=30×10×10=3000 J or 3 KJ
Answered by
0
Answer:
Explanation:
When the man travels with the load in the forward direction then the work done by him against the force of gravity is zero (because in this case cos = 90 degree).after this when the man rises 10 m in the vertical direction then the work done by him against the gravity is given by,
F×D=m×a×d=30×9.8×10=2940Joules.
Hope you have got the explanation
Similar questions