Question

A man cleaning a floor pulls a vacuum cleaner with a force of magnitude F = 50 N at an angle of 30° with the horizontal . Calculate the work done by the force on the vacuum cleaner as the vacuum cleaner is displaced 3 m to the right

in other case
if the force unknown and he give the mass and the angle
find the force net

Answer 1

Explanation:

Every information asked is in the attachment...

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PLZ MARK AS BRAINLIEST ... PLZ

Answer 2

Answer:

here mass is not participating in any role

Explanation:

so resolving of components

f=50

work done = force in direction of displacement x displacement

that equal to

                   =f cos 30 x30

                    =50 x $\sqrt{3/2}$ x 3

                    =75$\sqrt{3}$

                    =129.75

                     =130 j  

in case -2 if mass is then it will not affect the answer

then

W=f. cosФ

   = (mg) (cos 90) 3

    w=0

so here mass is not participating in any role

#SPJ2