Question

A man climbing a wall.For every 4 steps go up he will slipdown 2 steps.If he  takes 12 min to 3 steps.how much time it takes to climb 48meters and one step=2meters.​

Answer 1

Answer:

Height of the pole (x) = 15 m.

Climbed distance per minute(y)= 4m

Slips (y) = 2 m in next minute.

So, in 2 minute he climbs 2 m.

We take, 2 minute = 1 unit of time.

t = 2 minutes.

You can calculate required time by this formula: ( We are calculating it for 14 m.)

Reqd. time =[(ht. of pole - slipped distance)/(climbed distance - slipped distance)]*t

= [(x-z)/(y-z)]*t;

= [(14 - 2) / (4 -2)] *2

= (12/2) *2

= 6 *2

= 12 minutes.

And the last 1 m monkey will climb in 45 second becouse one he get up did not get slipped down.

So, Total time = 12 minutes 45 seconds

Answer 2

Answer:

1 step =

12÷3=4 minutes

4×48m

= 192 minutes