A man climbs on a wall 3.6m high and gains 2268J of P.E. find his mass
yashu63:
2268÷36= 62.8kg i.e. P.E. = mgh or m =P.E.÷g×h
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Answers
Answered by
14
we know that:
m*g*h=p.e.
m=2268/3.6*10
=2268/36
=63kg
m*g*h=p.e.
m=2268/3.6*10
=2268/36
=63kg
Answered by
41
Given,
Height of the wall = 3.6 m
Potential energy = 2268 J.
We know that Potential energy = Mass * g * height
P.E = mgh
2268= m * 9.8* 3.6
2268= m * 35.28
2268/35.28= m
m = 64.285 Kg. [ or ]
We can take g = 10
then,
2268= m * 10*3.6
2268/36= m
m = 63 Kg.
Mass of the body = 63 Kg
Height of the wall = 3.6 m
Potential energy = 2268 J.
We know that Potential energy = Mass * g * height
P.E = mgh
2268= m * 9.8* 3.6
2268= m * 35.28
2268/35.28= m
m = 64.285 Kg. [ or ]
We can take g = 10
then,
2268= m * 10*3.6
2268/36= m
m = 63 Kg.
Mass of the body = 63 Kg
Amazing explanation.... I understood it really well,Thanks a lot
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