Math, asked by seth58, 6 months ago


• A man collects milk at the rate of 8.50 per litre and after mixing some water therewith he
sells it at the same rate and thus gains 115 What proportion of water did he mix?​

Answers

Answered by shreya182010
3

Step-by-step explanation:

Lets assume we have 10 litres of milk and hence it will cost Rs 85 (CP)

Say, x litres of water is added to the mixture and there the final volume becomes (10+x) litres.

Given that he sells the mixture at cost price and gains 11.11% i.e. 1/9.

He sells this at Rs (10+x)*8.5 (SP)& makes a final profit of 1/9 %.

Therefore by equating the values in the formula ( SP/CP-1 = Profit% ) we get x= 1/9= o.111 litre

Answered by Aadichawla
1

Step-by-step explanation:

Lets assume we have 10 litres of milk and hence it will cost Rs 85 (CP)

Say, x litres of water is added to the mixture and there the final volume becomes (10+x) litres.

Given that he sells the mixture at cost price and gains 11.11% i.e. 1/9.

He sells this at Rs (10+x)*8.5 (SP)& makes a final profit of 1/9 %.

Therefore by equating the values in the formula ( SP/CP-1 = Profit% ) we get x= 1/9= o.111 litre

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