A man completed a trip of 136 km in 8 hours.
Some parts of the trip was covered at
15 km/hr and the remaining at 18 km/hr. Find
the part of the trip covered at 18 km/hr.
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Answer:
SOLUTION OF THIS QUESTION:
Total distance of the trip = 136 km
Let part of the trip covered at 18km/hr = x km
∴ Distance of the trip covered at 15km/hr = (136 – x) km
Time taken by the man to cover x km
= Distance/speed = (x/18) hours
Time taken by the man to cover (136 – x) km
= (136 – x)/15 hours
Total time taken by the man to cover a trip of 136 km = 8 hours
∴ x/18 + (136 – x)/15 = 8
⇒ x/18 × 90 + (136 – x)/15 × 90 = 8 × 90
[Multiplying each term by 90 because L.C.M. of denominators = 90]
⇒ 5x + 6 (136 – x) = 720
⇒ 5x + 816 – 6x = 720
⇒ 5x – 6x = 720 – 816
⇒ -x = -96
⇒ x = 96
∴ Part of the trip covered at 18km/ hr = 96 km
Step-by-step explanation:
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