a man completes a journey in 15hours he travels the first 1/3 of the journey on the rate of 30km per hour and 2/3 journey at 40km per hour. find the total distance of the journey
Answers
Step-by-step explanation:
Hi there!
Here's the answer:
•°•°•°•°•°<><><<><>><><>°•°•°•°•°•
Distance = Speed × Time
METHOD - 1 :
Total Journey made = 10 Hrs
Let total distance be d Km
First half of the distance /frac{d}{2}/fracd2 travelled at 21 kmph in x hrs
=> d/2 = 21xd/2=21x
=> d = 42xd=42x --------(1)
Second Half of the distance (d/2) travelled at 24 kmph in (10-x) Hrs
=> \frac{d}{2} = 24 × (10 - x)
2
d
=24×(10−x)
=> d = 48(10 - x)d=48(10−x)
=> x = 10 - (\frac{d}{42})x=10−(
42
d
) -------(2)
From eq(1) & eq(2)
=> \frac{d}{42} = 10 - (\frac{d}{48})
42
d
=10−(
48
d
)
=> \frac{d}{42} + \frac{d}{48} = 10
42
d
+
48
d
=10
=> d = \frac{2×5×2×3×7×8}{3×5}d=
3×5
2×5×2×3×7×8
=> d = 224 Kmsd=224Kms
•°• Required distance covered = 224 km
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Answer:
a man completes a journey in 15hours he travels the first 1/3 of the journey on the rate of 30km per hour and 2/3 journey at 40km per hour. find the total distance of the journey