Question

a man cover a certain distance on scooter and if he travel 3km per hr
faster ,he would have taken 40 min less. but if he decrease his speed by 2 km per hr then he becomes 40 min late.
find the distance.​

Answer 1

Answer:

40 km

Step-by-step explanation:

let s be speed

now,

s(s+3)/3 *40/60= s(s-2)/2*40/60

s=12

12*15/3 *40/60

40km

Answer 2

The distance is 40 km.

Step-by-step explanation:

Consider the provided information.

We need to find the distance.

Use the formula: $Speed=\dfrac{2v_1v_2}{v_1-v_2}$

It is given that if he travel 3 km per hr  faster, he would have taken 40 min less. If he decrease his speed by 2 km per hr then he becomes 40 min late.

$Speed=\dfrac{2(3)(2)}{3-2}=12$

Hence, the speed is 12 km per hour.

Now use the formula: $Distance =vt_1(1+\frac{v}{v_1})$

Substitute the respective values in above formula.

$Distance =12\times\frac{40}{60}(1+\frac{12}{3})$

$Distance =8(1+4)$

$Distance =40$

Hence, the distance is 40 km.

#Learn more

Please find the distance​

https://brainly.in/question/8544649