A man cover a distance of 200 km travelling with a uniform speed of 8 km per hour the distance would have been covered in 2 hours less at the speed been as + 5 km per hour calculate the value of x
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DISTANCE COVERED BY THE MAN =200 KM
UNIFORM SPEED =8 KM/H
SPEED INCREASE BEFORE 2 HOUR =8+5 KM/H=13 KM/H
DISTANCE COVERED BEFORE 2 HOURS=200-13*2=200-26 KM=174 KM
TIME TAKEN =DISTANCE COVERED / UNIFORM SPEED
=174 KM /8 KM/H
=21 HOURS 45 MINUTE
TOTAL TIME TAKEN TO COVER THE DISTANCE 200 KM
=21 HOURS 45 MINUTE + 2 HOURS
ANSWER=23 HOURS 45 MINUTE
UNIFORM SPEED =8 KM/H
SPEED INCREASE BEFORE 2 HOUR =8+5 KM/H=13 KM/H
DISTANCE COVERED BEFORE 2 HOURS=200-13*2=200-26 KM=174 KM
TIME TAKEN =DISTANCE COVERED / UNIFORM SPEED
=174 KM /8 KM/H
=21 HOURS 45 MINUTE
TOTAL TIME TAKEN TO COVER THE DISTANCE 200 KM
=21 HOURS 45 MINUTE + 2 HOURS
ANSWER=23 HOURS 45 MINUTE
Answered by
1
Answer:
Speed of the car =x km /hr
Time taken =t hrs
xt=200
∴t= x200
Now, (x+5)(t−2)=200
(x+5)( x 200/ −2)=200
(x+5)(200−2x)=200x
200x−2x
2 +1000−10x=200x
x /2 +5x−500=0
x /2 +25x−20x−500=0
(x+25)(x−20)=0
x=−25,x=20
Speed cannot be negative value, hence, x=20 km/hr
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