a man covered 3/7 of his journey by boat,2/7 of his journey by train and the remaining 12 km by foot .what was the total distance travled
Answers
Answered by
2
Let x = total journey distance
by train + by taxi + by bus + by foot = total journey
(2/5)x + (1/3)x + (1/6)x + 10K = x
To get rid of all fractions, multiply by the LCM of the denominators (this is just like finding the Least Common Denominator). LCM = 30
12x + 10x + 5x + 300K = 30x
27x + 300K = 30x [group like terms]
300K = 3x [subtract 27x from both sides]
100K = x [divide both sides by 3]
The total journey was 100 K
by train + by taxi + by bus + by foot = total journey
(2/5)x + (1/3)x + (1/6)x + 10K = x
To get rid of all fractions, multiply by the LCM of the denominators (this is just like finding the Least Common Denominator). LCM = 30
12x + 10x + 5x + 300K = 30x
27x + 300K = 30x [group like terms]
300K = 3x [subtract 27x from both sides]
100K = x [divide both sides by 3]
The total journey was 100 K
mirjavaid7:
wow
Answered by
3
Answer:42 km
Step-by-step explanation:let the total distance covered be (x)
A.T.Q
3/7(x) + 2/7(x) +12=(x)
5/7(x)+12=(x)
(x)-5/7(x)=12
2/7(x)=12
(x)=42
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