A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is:
Answers
Answered by
45
hlo dear friend
according to given condition
vt=(v+3)(t-2/3)
vt=(v-2)(t+2/3)
here v is velocity in kmph,t is time in hours and 2/3 is value of 40 min in hours
on solving we get t=10/3 ,v=12
so distance = vt =10/3*12=40
hope u understand
according to given condition
vt=(v+3)(t-2/3)
vt=(v-2)(t+2/3)
here v is velocity in kmph,t is time in hours and 2/3 is value of 40 min in hours
on solving we get t=10/3 ,v=12
so distance = vt =10/3*12=40
hope u understand
Answered by
0
Distance =S1S2/(S1−S2)×t
from both conditions,
S(S+3)3×40=S(S−2)2×40
2S+6=3S−6
S = 12 km/hr
from condition 1st
12×153×4060 = 40 km
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