A man covered a certain distance at some speed.had he moved 3kmph faster,he would have taken 40 mins less.if he had moved 2kmph slower ,he would have taken 40mins more.what is the distance?
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According to given condition
vt=(v+3)(t-2/3)
vt=(v-2)(t+2/3)
here v is velocity in kmph, t is time in hours and 2/3 is value of 40 min in hour
on solving we will get t=10/3 and and v = 12 so distance = (10/3) * 12 = 40 kms
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