Math, asked by preetiguptarocks99, 5 months ago


A man covers 300 km distance by train, bus, and car in
ratio 12:8:5. Fairs of these vehicle are in ratio 2:3:6
respectively. If man can travels 1 km by bus for 0.60.
then for covering hole distance. How much money he
have to expend for fairs,

Answers

Answered by veerajagarwal
0

Answer:

Step-by-step explanation:

Let, the speed of train be x & speed of bus be y.

Speed=  

Time

Distance

 or T=  

S

D

 

4=  

x

60

+  

y

240

 ………….(1)

4 hr 10 min=  

x

100

+  

y

200

 ………..(2)

(1)×5

20=  

x

300

+  

y

240×S

 

(2)×3

62

25×3

=  

x

300

+  

y

600

 

20−  

2

25

=  

y

1200

−  

y

600

 

2

15

=  

y

600

 

y=80 km/ph

4=  

x

60

+  

80

240

 

x=60 km/ph.

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