A man covers 5 min in 2 seconds,taking a turn he covers 6 m in next 4 second and 3 m in another seconds. Then his motion is .......... motion
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Answer:
Let the initial velocity of the body be u m/s; and the constsnt acceleration be a m/s². Then displacemet (distance covered) of the body after t second is given by
s = u t + ½ a t² ———————————-(1)
The body covers 20 m in 2s and 80 m in 4 s.
20 = u×2 + ½ a 2²; => 20 = 2 u + 2 a
u + a = 10 —————————————(2)
80 = u×4 + ½ a 4²; => 80 = 4 u + 8 a; this gives,
u + 2 a = 20 ——————————————(3)
Solving (2) and (3) for u and a we get
u = 0 m/s and a = 10 m/s² ————————(4)
To obtain the distance covered in the next 4s we need to find the velocity at the beginning of this interval using,
v = u + a t => v = 0 m/s + 10 m/s² ×4s = 40m/s
s = u t + ½ a t²
Substituting various values we get
s = 40×4 +½ ×10×4² = 160 + 80= 240 m
The body will cover 240 m in the next 4 seconds
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