A man covers a certain distance between his house and office on a scooter having average speed 30 kmph. He is late by 10 mins, however with the speed of 40 kmph he reaches his office 5 min. Earlier. Find the distance between his house and office?
a.30 km
b.50 km
Answers
Answered by
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Let us assume that your school time is 9:00 AM.
let us assume you reaches school 10 min late, therefore you reaches at 9:10 AM
and let us think that your friend reaches 5 min earlier, therefore he reaches at 8:55 AM.
the difference in time is 10+5 = 15 min.
hope this helps you.
let us assume you reaches school 10 min late, therefore you reaches at 9:10 AM
and let us think that your friend reaches 5 min earlier, therefore he reaches at 8:55 AM.
the difference in time is 10+5 = 15 min.
hope this helps you.
Answered by
0
Answer:
x/30-x/40=10+5min/60
x/30+x/40= 15/60
4x-3x/120=1/4
x/120= 1/4
x=120/4
x= 30km
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