a man covers a certain distance on scooter. had he moved 3 kmph faster, he would have taken 40 minutes less. if he had moved 2 kmph slower, he would have taken 40 minutes more. the distance is
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Answer:
speed
=
2
v
1
v
2
v
1
−
v
2
=
2
×
3
×
2
3
−
2
=
12
km/hr
distance
=
v
t
1
(
1
+
v
v
1
)
=
12
×
40
60
(
1
+
12
3
)
=
40
km
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