a man covers a distance of 24 kilometre in 3.5 hours partly on foot at the speed of 4.5 km per hour and partly on bicycle at the speed of 10 km per hour. find the distance covered on foot
Answers
Step-by-step explanation:
Answer:
The distance covered on foot is 9 km.
Step-by-step explanation:
Given : A man covers a distance of 24 km in 3 and a half hours partly on foot at he speed of 4.5 km/h and partly on bicycle at the speed of 10 km/hr.
To find : The distance covered on foot ?
Solution :
Let the distance covered on foot be 's'.
Total distance covered is 24 km.
The distance covered by bicycle is '24-s'.
Speed on foot is 4.5 km/h.
Speed on bicycle is 10 km/hr.
Total time cover by foot and bicycle = 3.5 hours.
We know, \text{Time}=\frac{\text{Distance}}{\text{Speed}}Time=
Speed
Distance
Then,
\frac{s}{4.5}+\frac{24-s}{10}=3.5
4.5
s
+
10
24−s
=3.5
Solving the equation,
\frac{10s+4.5(24-s)}{4.5\times 10}=3.5
4.5×10
10s+4.5(24−s)
=3.5
\frac{10s+108-4.5s}{45}=3.5
45
10s+108−4.5s
=3.5
108+5.5s=3.5\times 45108+5.5s=3.5×45
108+5.5s=157.5108+5.5s=157.5
5.5s=157.5-1085.5s=157.5−108
5.5s=49.55.5s=49.5
s=\frac{49.5}{5.5}s=
5.5
49.5
s=9s=9
Therefore, The distance covered on foot is 9 km.
Answer:
9 miles
Step-by-step explanation:
Let w = his distance on foot
the total distance is given as 24 km, therefore
(24-w) = dist by bicycle
Write a time equation, time = dist/speed
Walk time + bike time = 3.5 hrs
multiply by 90 to clear the denominators
20w + 9(24-w) = 90(3.5)
20w + 216 - 9w = 315
20w - 9w = 315 - 216
11w = 99
w = 99'/11
w = 9 mi on foot