a man covers a distance of 6 km at the rate 4 kmph and other 4 km at 3kmph. his average speed is
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d 1 =6 km
d 2=4 km
s 1=4 km/h
s 2=3 km/h
t 1=6/4=1.5 s or 3/2
t 2=4/3
average speed=total d/total/t
10/3/2+4/3
10/6+8/6
10/14/6
10/7/3
10*3/7
30/7 is the average velocity
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Answer:
Step-by-step explanation:
Average speed =total distance/time taken
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