Question

A man covers x km in t hours at s km/hr ; another man covers x/2 km in 2t hours at r km/hr.Then the ratio s:r equals?

Answer 1

A man covers x km in t hours at s km/hr ; another man covers x/2 km in 2t hours at r km/hr.Then the ratio s:r equals?

Answer 2

The required ratio s:r is equal to  4:1.

Step-by-step explanation:

Given:

x km distance a man covers in t hours at s km/hr.

$\frac{x}{2}$ km distance another man in 2t hours at r km/hr.

To Find:

The required ratio s:r.

Formula Used:

p =  d/q                 ---------------- formula no.01

where

        p = speed

        d = distance covered

        q= time taken to cover distance

Solution:

As given- x km distance a man covers in t hours at s km/hr.

p =s km/hr , d=x km   and q= t  hours

putting value of p, d and t in formula no .01

 $s=\frac{x}{t}$

As given - $\frac{x}{2}$  km distance another man covers in 2t hours at r km/hr.

 p =r km/hr , d=$\frac{x}{2}$ km   and q= 2t  hours

 putting value of p, d and t in formula no .01

 $r= \frac{(\frac{x}{2} )}{2t}$  

 $r= \frac{x}{4t}$  

The required ratio $s:r = \frac{x}{t} :\frac{x}{4t}$

                                $s:r = 1 :\frac{1}{4}$

                                $s:r = 4 :1$

Thus, the required ratio s:r is equal  to 4:1.