Question

A man crosses a distance of 88 m while going round a rectangular field of length 17 m twice. Find the breadth of the field.

Please solve this math. ​

Answer 1

Answer:

5m

Step-by-step explanation:

perimeter - 88/2 =>44

2(17 + x )=44

17+x = 22

x = 5

Answer 2

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$\\ \large \underline{ \underline{ \sf \star \: given : }} \\ \\ \large \sf \: length = 17m \\ \\ \large \sf \: distance = 88m \\ \\ \large \sf \: field \: \: travelled \: \: twice..$

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$\\ \large \red{ \sf \: solving - \: } \\ \\ \large \sf \: perimeter \: \: of \: \: rectangle : \\ \\ \large \sf : \implies \: p = \frac{88}{2} \\ \\ \\ \large \sf : \implies \: p = \frac{ \cancel{88} \: \: 44}{ \cancel2} \\ \\ \\ \large \tt \therefore \: \underline{ \pink{ \tt \: perimeter = 44m}}$

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$\\ \large \sf \: using \: \: formula : \\ \\ \large \tt \: perimeter = \\ \large \: \: \: \sf \boxed{ \tt \green{2(length + breadth)}} \\ \\ \\ \large \tt : \implies \: p = 2(17 + b) \\ \\ \large \tt : \implies \: 44= 2(17 + b) \\ \\ \large \tt : \implies \: \frac{44}{2} = 17 + b\\ \\ \large \tt : \implies \: \frac{ \cancel{44} \: \: 22}{ \cancel2} = 17 + b\\ \\ \large \tt : \implies \: 22= 17 + b\\ \\ \large \tt : \implies \: 22 - 17 = breadth\\ \\ \large\therefore \sf \red{ \underline{ \underline{ \blue{ \sf \: breadth = 5m}}}}$

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