a man crosses a river in a Boat. if he crosses the river in minimum time he takes 10 min with the drift of 120 m . if he crosses the river taking the shortest path ,he takes 12.5 min then find width of the river
Answers
Explanation:
Width = d
Man = V
River = v
In minimum time, he goes perpendicular to the river.
d/V = 10 min------(1)
v x 10 min = 120 m, so v = 12 m /min
In minimum distance, the resultant of the velocities is perpendicular to river
If he is at angle x with the perpendicular
V sinx = v = 12-----(2)
V cosx = d / 12.5-----(3)
Squaring and adding (2) and (3)
2V^2 = 144 + d^2 / 156.25 -----(4)
Putting value of V from (1) in (4),
d^2 /50 = 144 + d^2 /156.25
d^2 = 10500 m
d = 100m
There could be some calculation error, but the method is correct.
Answer:
Explanation:
Width = d
Man = V
River = v
In minimum time, he goes perpendicular to the river.
d/V = 10 min------(1)
v x 10 min = 120 m, so v = 12 m /min
In minimum distance, the resultant of the velocities is perpendicular to river
If he is at angle x with the perpendicular
V sinx = v = 12-----(2)
V cosx = d / 12.5-----(3)
Squaring and adding (2) and (3)
2V^2 = 144 + d^2 / 156.25 -----(4)
Putting value of V from (1) in (4),
d^2 /50 = 144 + d^2 /156.25
d^2 = 10500 m
d = 100m
There could be some calculation error, but the method is correct.