A man cycles at the speed of 8 km/hr and reaches office at 11 am and when he cycles at the speed of 12 kmph he reaches office at 9 am.At what speed should he cycle so that he reaches his office at 10 am
Anonymous:
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Answers
Answered by
1
the answer is 10 km/hr as it is between 9 and 11
Answered by
18
Hello Dear,
◆ Answer -
v = 9.6 km/hr
◆ Explanation -
Let x be the distance to be travelled & t be the time required to reach office in first case.
In 1st case,
8 = x / t
∴ x = 8t ...(1)
In 2nd case,
12 = x / t-2
∴ x = 12(t-2) ...(2)
Equating (1) & (2),
8t = 12(t-2)
8t = 12t - 24
4t = 24
t = 6 hrs
Putting this in (1),
x = 8t
x = 8 × 6
x = 48 km
When he have to reach at 10 am,
v = x / t-1
v = 48 / (6-1)
v = 48 / 5
v = 9.6 km/hr
Therefore, the man have to cycle at the speed of 9.6 km/hr to reach office at 10 am.
Hope this is helpful.
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