Question

- A man cycles from A to B, a separation of 21 km in 1 hr 40 min. The street

from A is level for 13 km and afterward it is tough to B. The man's normal rate on

level is 15 km/hr. Locate his normal tough pace​

Answer 1

Answer:

Distance travelled on level road =13km

Average speed on level road =15km/hr

Time travelled on level road =Distance /Av speed

=13km\15km

hr)

=0.87hours

Distance travel uphill =8km

(21km—13km)

Time travelled uphill = 1 hour 40 mins -52

mins = 48mins

Average speed uphill =Distance

Travelled/Timetakaen

8km/ (48/60) hrs =10km/hr