A man decides to pave with square tiles which is 4.8 metres long and 5.38 metre wide find the largest size of the tile that he could use
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Hey there !!
The length of area to be paved = 4.8m
The breadth of area to be paved = 5.38
now ,
area of the space that can be paved = Length × breadth .
area = 4.8 × 5.38 = 25.84m²
now ,
let us suppose that 25.84m² is the area of the square
side of of square tile = √25.84 = 5.08.. m
hence the side of the tile will be 5.08m and the area of the largest square tile that he can use for paving is 25.84m².
The length of area to be paved = 4.8m
The breadth of area to be paved = 5.38
now ,
area of the space that can be paved = Length × breadth .
area = 4.8 × 5.38 = 25.84m²
now ,
let us suppose that 25.84m² is the area of the square
side of of square tile = √25.84 = 5.08.. m
hence the side of the tile will be 5.08m and the area of the largest square tile that he can use for paving is 25.84m².
Answered by
1
Answer:
5.08 m
Step-by-step explanation:
rectangular area to be covered= 4.8*5.38 = 25.824
as the tiles are square
length of each tiles = √25.824 = 5.08
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