Question

A man deposit a total amount of Rs. 65,000 in 3 banks A B and C at the rate of simple interest 12%, 16% and 18% respectively and earn a total SI of Rs. 10,180 in one year.

If the amount invested in bank A was 71(3/7)% of amoun 7 invest in bank C. Find the amount invested in bank B.​

Answer 1

Answer:

21000Rs

Step-by-step explanation:

71 3/7%=5/7

A+C combined rate =15.5%

B=16%

15.5% [0% 0.5%]

SI= 65000*15.5/100=10075Rs

change in SI=10180-10075=105Rs

0.5% of B=105

100% of B=105*100/0.5=21000Rs

Answer 2

The amount invested in Bank B is Rs. 11122

Given:

A man deposit a total amount of Rs. 65,000 in 3 banks A B and C at the rate of simple interest of 12%, 16%, and 18% respectively and earn a total SI of Rs. 10,180 in one year.

The amount invested in bank A was 71(3/7)% of the amount invested in bank C.

To find:

Find the amount invested in bank B.​

Solution:

Let's assume that the amount invested in Bank C is x.

Then the amount invested in Bank A = 71.43% of x = 0.7143x

Let 'y' be the amount invested by B

The total amount invested is Rs. 65,000

x + 0.7143x + y = 65,000

=> y = 65000 - 1.7143x  ---- (1)

The total amount of simple interest earned in one year is Rs. 10,180.

Using the formula for simple interest:

SI = P × R × T / 100

Simple interest for (A) = 0.7143x × 12 × 1/100 = 0.0857x  

Simple interest for (B) = y × 16 × 1 /100 = 0.16y

Simple interest for (C) = x × 18 × 1 /100 = 0.18x

Adding these equations

0.0857x + 0.16y + 0.18x = 10,180

On Simplifying we get:

0.267x + 0.16y = 10,180

Substituting the expression (1) for x value

0.267x + 0.16(65000 - 1.7143x ) = 10,180

Simplifying and solving for x, we get:

0.267x + 10400 - 0.274x = 10,180

=> - 0.007x = 10180 - 10400

=> 0.007x = 220

=> x = 31428.57

Substitute x in (1)

=> y = 65000 - 1.7143(31428.57)

=> y = 65000 - 53878

=> y = 11122

Therefore,

The amount invested in Bank B is Rs. 11122

Learn more at

https://brainly.in/question/18069646

#SPJ3