Question

A man deposited 18000 in bank for one year to earn some interest if the same interest is to be earn 8 months at the same rate what sum should be deposited by him
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Answer 1

Answer:

If the same interest is to be earn in 8 months at the same rate, the sum should be deposit by him = Rs 27,000

Step-by-step explanation:

Case 1:

Principal ( P ) = Rs 18,000

Time ( T ) = 1 year

Rate = R

Since ,

   S.I = $\frac{P*T*R}{100}$

⇒ S.I = $\frac{18000*R*1}{100}$

⇒ S.I = 180 × R                  equation ( i )

Case 2:

Principal = P

Rate = R

Time = 8 months  = $\frac{8}{12}$ year

Since,

   S.I = $\frac{P*T*R}{100}$

⇒ S.I = $\frac{P*8*R}{12*100}$                      equation ( ii )

According to question

    equation ( i ) = equation ( ii )

⇒ 180 × R = $\frac{P*8*R}{12*100}$

⇒ 180 × R × 12 × 100 = P × 8 × R

⇒ P = $\frac{180*12*100}{8}$

∴ P = Rs 27,000

Therefore,

If the same interest is to be earn in 8 months at the same rate, the sum should be deposit by him = Rs 27,000.

Answer 2

Answer:

If the same interest is to be earn in 8 months at the same rate, the sum should be deposit by him = Rs 27,000

Step-by-step explanation:

Case 1:

Principal ( P ) = Rs 18,000

Time ( T ) = 1 year

Rate = R

Since ,

S.I = \frac{P*T*R}{100}

100

P∗T∗R

⇒ S.I = \frac{18000*R*1}{100}

100

18000∗R∗1

⇒ S.I = 180 × R equation ( i )

Case 2:

Principal = P

Rate = R

Time = 8 months = \frac{8}{12}

12

8

year

Since,

S.I = \frac{P*T*R}{100}

100

P∗T∗R

⇒ S.I = \frac{P*8*R}{12*100}

12∗100

P∗8∗R

equation ( ii )

According to question

equation ( i ) = equation ( ii )

⇒ 180 × R = \frac{P*8*R}{12*100}

12∗100

P∗8∗R

⇒ 180 × R × 12 × 100 = P × 8 × R

⇒ P = \frac{180*12*100}{8}

8

180∗12∗100

∴ P = Rs 27,000

Therefore,

If the same interest is to be earn in 8 months at the same rate, the sum should be deposit by him = Rs 27,000.