Math, asked by gargvanshika229, 1 day ago

A man deposited ₹7,505 on March 18 when the rate of interest was 3⅓% p.a. The rate of interest was raised to 3¾% p.a. on 16th May and then it was reduced to 3¼% p.a. on 1st August. Calculate interest payable on 25th November. ​

Answers

Answered by krishna1453
2

Answer:

No. of Days:

March- 13 days

April-30 days

May-15 days

Rate of Interest=10/3%

Amount= Rs.7505/-

Interest Amount from March 18 to 15th May:

7505 X 10/3%=7505 x 1/30=250.17 per annum

For 58 days, interest is: (250.17/365) X 58 days

=39.75

Interest rate was 15/4% from 16 May to 31st July

No. of days=15 days(May) +30 days(June) +31 days(July)=76 days

Interest= 7505*15/4%=281.44 per annum

For 76 days=(281.44/365 days) X 76 days=58.60

No. of days from 1st August to 25th November=

31 days + 30 days+31 days+25 days=117 days

7505 X 13/4 %=243.91 per annum

Interest:(243.91/365) X117 days=78.18

Total interest payable:78.18+58.60+39.75=176.53=177

Step-by-step explanation:

Similar questions